If man distributes 6 coins randomly among 3 safes. How many different distributions of the coins is there.?
Public Comments
- 18
- 216 6 x 6 x 6
- 15 like - 1.2.3.4.5.6 12 13 14 15 16 23 24 25 26 34 35 36 45 46 56
- 0 in the first safe gives 7 possibilities for the second safe (6,2,4,3,2,1,0) each of which gives only one choice for the last (put any left in it) 1 in the first safe gives 6 possibilities for the second safe 2 in the first safe gives 5 possibilities for the second safe 3 in the first safe gives 4 possibilities for the second safe 4 in the first safe gives 3 possibilities for the second safe 5 in the first safe gives 2 possibilities for the second safe 6 in the first safe gives 1 possibility for the second safe 7+6+5+4+3+2+1 = 28 total
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