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A 44-kg pole vaulter running at 10 m/s vaults over the bar. Whats the m as she crosses the bar?

A 44-kg pole vaulter running at 10 m/s vaults over the bar. Her speed when she is above the bar is 0.7 m/s. Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar. Determine her altitude as she crosses the bar in m.

Public Comments

1. use conservation of energy the vaulter's KE before vaulting equals the sum of PE plus KE at max ht we have 1/2 m v0^2 = m g h + 1/2 m v^2 where v0 is the speed running, v is the speed going over the bar, h is the height going over the bar 1/2 (10m/s)^2 = 9.8m/s/s x h + 1/2 (0.7m/s)^2 50 - 0.245 = 9.8 h h = 5.08 m (this is how high her center of mass has risen above the height of the center of mass while running)